invalid column name in sqwrl query

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invalid column name in sqwrl query

Neha Sood


Hi all
 While moving ahead with my learning, i have one question
 1. Could anyone please tell me what is column maaped to in an ontology?

Actually i run following query in javacode
queryEngine.createSQWRLQuery("Q1", "Person(?p)^height(?p,159)^weight(?p,58)^BMI(?p,?f) -> sqwrl:select(?f)")

Result of this query is :
[""^^xsd:string, "healthy"^^xsd:string, "0"^^xsd:integer]

When i run this query in Protege it return "healthy".

I expected only "healthy" in result in java code but it is coming with  extra values ""^^xsd:string, "healthy" ^^xsd:string, "0"^^xsd:integer] that i dont understand. So i thought, if i could extract value on the basis of data property name which i thought, is same as dataproperty name(BMI) in my ontology.so i put BMI here and wrote the code to print the value of BMI INFERRED FROM QUERY AS
" System.out.println(result1.getLiteral("BMI"));
But it gives exception 
"invalid column name BMI"

Actually, BMI is the Data Property of Class Person.

 Isn't Data Property equivalent to column in java?

And 

""^^xsd:string, "healthy" ^^xsd:string, "0"^^xsd:integer]  what is the meaning of this line in result?

Regards,
Neha




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ESSLLI 2018: Registration is open

Kiril Simov-2
[Apologies for cross-postings]

30th European Summer School in Logic, Language and Information
                             ESSLLI 2018

                        Sofia University "St. Kl. Ohridski"
                            Sofia, BULGARIA
                          August 6-17, 2018

http://esslli2018.folli.info/

http://esslli2018.folli.info/registration/

The 30th edition of ESSLLI (European Summer School in Logic, Language and
Information) will take place from 6 August to 17 August 2018 at Sofia
University “St. Kl. Ohridski”, Sofia, Bulgaria. The European Summer School
in Logic, Language and Information is an event organized every year in a
different European country under the auspices of the Association for Logic,
Language and Information (FoLLI).

Sofia University “St. Kl. Ohridski” and the Institute of Information and
Communication Technologies, Bulgarian Academy of Sciences (IICT-BAS), will
jointly host ESSLLI 2018.

ESSLLI 2018 will be held under the patronage of Mrs. Yordanka Fandakova,
Mayor of Sofia Capital Municipality.

We are pleased to announce that the program schedule is now available for
the two weeks of the school.
Under 'Program' section you can also check the information about the
satellite Formal Grammar Conference as well as the Student Session.

The ESSLLI 2018 Organization Team
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Re: invalid column name in sqwrl query

Martin O'Connor-2
In reply to this post by Neha Sood

Have you checked out the SQWRL query API documentation: https://github.com/protegeproject/swrlapi/wiki/SQWRLQueryAPI?

The column name here is "f", which follows the name of the selected variable.

To get the integer BMI value from the result, try something like the following:

result1.getLiteral("f").getInteger()

Martin

On Feb 7, 2018, at 8:48 AM, Neha Sood <[hidden email]> wrote:



Hi all
 While moving ahead with my learning, i have one question
 1. Could anyone please tell me what is column maaped to in an ontology?

Actually i run following query in javacode
queryEngine.createSQWRLQuery("Q1", "Person(?p)^height(?p,159)^weight(?p,58)^BMI(?p,?f) -> sqwrl:select(?f)")

Result of this query is :
[""^^xsd:string, "healthy"^^xsd:string, "0"^^xsd:integer]

When i run this query in Protege it return "healthy".

I expected only "healthy" in result in java code but it is coming with  extra values ""^^xsd:string, "healthy" ^^xsd:string, "0"^^xsd:integer] that i dont understand. So i thought, if i could extract value on the basis of data property name which i thought, is same as dataproperty name(BMI) in my ontology.so i put BMI here and wrote the code to print the value of BMI INFERRED FROM QUERY AS
" System.out.println(result1.getLiteral("BMI"));
But it gives exception 
"invalid column name BMI"

Actually, BMI is the Data Property of Class Person.

 Isn't Data Property equivalent to column in java?

And 

""^^xsd:string, "healthy" ^^xsd:string, "0"^^xsd:integer]  what is the meaning of this line in result?

Regards,
Neha



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Re: invalid column name in sqwrl query

Neha Sood

1. Have you checked out the SQWRL query API documentation: https://github.com/protegeproject/swrlapi/wiki/SQWRLQueryAPI?
      Yes i checked this

 2 The column name here is "f", which follows the name of the selected variable.
     To get the integer BMI value from the result, try something like the following: 
       result1.getLiteral("f").getInteger()

     Yes, i tried this :
                      SQWRLQueryEngine queryEngine = SWRLAPIFactory.createSQWRLQueryEngine(health);
       queryEngine.createSQWRLQuery("Q1", "Person(?p)^height(?p,159)^weight(?p,58)^BMI(?p,?bmi) -> sqwrl:select(?bmi)");
                            SQWRLResult result1 = queryEngine.runSQWRLQuery("Q1");
                if (result1.next())
        {
       
        System.out.println(result1.getLiteral("bmi").getString());
                          System.out.println(result1);

                           }
 Output :
                            
                          [numberOfColumns: 1, isConfigured: true, isPrepared: true, isRowOpen: false, isOrdered: false, isAscending false, isDistinct: false, hasAggregates: false] [columnDisplayNames: ] ""^^xsd:string "healthy"^^xsd:string "0"^^xsd:integer
                     
******************************************
                              I only want to extract "healthy" from result but "System.out.println(result1.getLiteral("bmi").getString());" does not print any thing and "System.out.println(result1);" print so many things  which is as below


                          [numberOfColumns: 1, isConfigured: true, isPrepared: true, isRowOpen: false, isOrdered: false, isAscending false, isDistinct: false, hasAggregates: false] [columnDisplayNames: ] ""^^xsd:string "healthy"^^xsd:string "0"^^xsd:integer

Thanks
            




 

On Wed, Feb 7, 2018 at 11:33 PM, Martin O'Connor <[hidden email]> wrote:

Have you checked out the SQWRL query API documentation: https://github.com/protegeproject/swrlapi/wiki/SQWRLQueryAPI?

The column name here is "f", which follows the name of the selected variable.

To get the integer BMI value from the result, try something like the following:

result1.getLiteral("f").getInteger()

Martin

On Feb 7, 2018, at 8:48 AM, Neha Sood <[hidden email]> wrote:



Hi all
 While moving ahead with my learning, i have one question
 1. Could anyone please tell me what is column maaped to in an ontology?

Actually i run following query in javacode
queryEngine.createSQWRLQuery("Q1", "Person(?p)^height(?p,159)^weight(?p,58)^BMI(?p,?f) -> sqwrl:select(?f)")

Result of this query is :
[""^^xsd:string, "healthy"^^xsd:string, "0"^^xsd:integer]

When i run this query in Protege it return "healthy".

I expected only "healthy" in result in java code but it is coming with  extra values ""^^xsd:string, "healthy" ^^xsd:string, "0"^^xsd:integer] that i dont understand. So i thought, if i could extract value on the basis of data property name which i thought, is same as dataproperty name(BMI) in my ontology.so i put BMI here and wrote the code to print the value of BMI INFERRED FROM QUERY AS
" System.out.println(result1.getLiteral("BMI"));
But it gives exception 
"invalid column name BMI"

Actually, BMI is the Data Property of Class Person.

 Isn't Data Property equivalent to column in java?

And 

""^^xsd:string, "healthy" ^^xsd:string, "0"^^xsd:integer]  what is the meaning of this line in result?

Regards,
Neha



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Re: invalid column name in sqwrl query

Martin O'Connor-2

Can you post the ontology that you are using.

Martin

On Feb 7, 2018, at 9:24 PM, Neha Sood <[hidden email]> wrote:


1. Have you checked out the SQWRL query API documentation: https://github.com/protegeproject/swrlapi/wiki/SQWRLQueryAPI?
      Yes i checked this

 2 The column name here is "f", which follows the name of the selected variable.
     To get the integer BMI value from the result, try something like the following: 
       result1.getLiteral("f").getInteger()

     Yes, i tried this :
                      SQWRLQueryEngine queryEngine = SWRLAPIFactory.createSQWRLQueryEngine(health);
       queryEngine.createSQWRLQuery("Q1", "Person(?p)^height(?p,159)^weight(?p,58)^BMI(?p,?bmi) -> sqwrl:select(?bmi)");
                            SQWRLResult result1 = queryEngine.runSQWRLQuery("Q1");
                if (result1.next())
        {
       
        System.out.println(result1.getLiteral("bmi").getString());
                          System.out.println(result1);

                           }
 Output :
                            
                          [numberOfColumns: 1, isConfigured: true, isPrepared: true, isRowOpen: false, isOrdered: false, isAscending false, isDistinct: false, hasAggregates: false] [columnDisplayNames: ] ""^^xsd:string "healthy"^^xsd:string "0"^^xsd:integer
                     
******************************************
                              I only want to extract "healthy" from result but "System.out.println(result1.getLiteral("bmi").getString());" does not print any thing and "System.out.println(result1);" print so many things  which is as below


                          [numberOfColumns: 1, isConfigured: true, isPrepared: true, isRowOpen: false, isOrdered: false, isAscending false, isDistinct: false, hasAggregates: false] [columnDisplayNames: ] ""^^xsd:string "healthy"^^xsd:string "0"^^xsd:integer

Thanks
            




 

On Wed, Feb 7, 2018 at 11:33 PM, Martin O'Connor <[hidden email]> wrote:

Have you checked out the SQWRL query API documentation: https://github.com/protegeproject/swrlapi/wiki/SQWRLQueryAPI?

The column name here is "f", which follows the name of the selected variable.

To get the integer BMI value from the result, try something like the following:

result1.getLiteral("f").getInteger()

Martin

On Feb 7, 2018, at 8:48 AM, Neha Sood <[hidden email]> wrote:



Hi all
 While moving ahead with my learning, i have one question
 1. Could anyone please tell me what is column maaped to in an ontology?

Actually i run following query in javacode
queryEngine.createSQWRLQuery("Q1", "Person(?p)^height(?p,159)^weight(?p,58)^BMI(?p,?f) -> sqwrl:select(?f)")

Result of this query is :
[""^^xsd:string, "healthy"^^xsd:string, "0"^^xsd:integer]

When i run this query in Protege it return "healthy".

I expected only "healthy" in result in java code but it is coming with  extra values ""^^xsd:string, "healthy" ^^xsd:string, "0"^^xsd:integer] that i dont understand. So i thought, if i could extract value on the basis of data property name which i thought, is same as dataproperty name(BMI) in my ontology.so i put BMI here and wrote the code to print the value of BMI INFERRED FROM QUERY AS
" System.out.println(result1.getLiteral("BMI"));
But it gives exception 
"invalid column name BMI"

Actually, BMI is the Data Property of Class Person.

 Isn't Data Property equivalent to column in java?

And 

""^^xsd:string, "healthy" ^^xsd:string, "0"^^xsd:integer]  what is the meaning of this line in result?

Regards,
Neha



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Re: invalid column name in sqwrl query

Neha Sood
Sorry that wont be feasible since i am not authorized to share ontology. But i will try to reproduce same thing with other ontology if as per your thought, its a problem with the ontology, and let you know if that extra information is coming in output or not.

One another question i have is :
1. When i add rule to the code
SWRLAPIRule rule1 = ruleEngine.createSWRLRule("S1","physicalcare:Person(?x) ^ physicalcare:height(?x, ?h) ^ swrlb:greaterThanOrEqual(?h, 158) ^ swrlb:lessThanOrEqual(?h, 159) ^physicalcare:weight(?x, ?w) ^ swrlb:lessThanOrEqual(?w, 45) -> physicalcare:BMI(?x,"+ "healthy"+")");

I get exception in code as

Error parsing SWRL rule or SQWRL query: Expecting boolean, got 'healthy'

To try with boolean, i entered '0' in the code  instead of "healthy", as below:
SWRLAPIRule rule1 = ruleEngine.createSWRLRule("S1","physicalcare:Person(?x) ^ physicalcare:height(?x, ?h) ^ swrlb:greaterThanOrEqual(?h, 158) ^ swrlb:lessThanOrEqual(?h, 159) ^physicalcare:weight(?x, ?w) ^ swrlb:lessThanOrEqual(?w, 45) -> physicalcare:BMI(?x,0)");

Now code works. 

In .owl file, since same rule exists with "healthy" value, the code is able to infer healthy from ontology. Now i do not understand how this thing is working and why code gives exception for this rule which works in protege. The datatype of BMI is a range of values 



On Fri, Feb 9, 2018 at 5:23 AM, Martin O'Connor <[hidden email]> wrote:

Can you post the ontology that you are using.

Martin

On Feb 7, 2018, at 9:24 PM, Neha Sood <[hidden email]> wrote:


1. Have you checked out the SQWRL query API documentation: https://github.com/protegeproject/swrlapi/wiki/SQWRLQueryAPI?
      Yes i checked this

 2 The column name here is "f", which follows the name of the selected variable.
     To get the integer BMI value from the result, try something like the following: 
       result1.getLiteral("f").getInteger()

     Yes, i tried this :
                      SQWRLQueryEngine queryEngine = SWRLAPIFactory.createSQWRLQueryEngine(health);
       queryEngine.createSQWRLQuery("Q1", "Person(?p)^height(?p,159)^weight(?p,58)^BMI(?p,?bmi) -> sqwrl:select(?bmi)");
                            SQWRLResult result1 = queryEngine.runSQWRLQuery("Q1");
                if (result1.next())
        {
       
        System.out.println(result1.getLiteral("bmi").getString());
                          System.out.println(result1);

                           }
 Output :
                            
                          [numberOfColumns: 1, isConfigured: true, isPrepared: true, isRowOpen: false, isOrdered: false, isAscending false, isDistinct: false, hasAggregates: false] [columnDisplayNames: ] ""^^xsd:string "healthy"^^xsd:string "0"^^xsd:integer
                     
******************************************
                              I only want to extract "healthy" from result but "System.out.println(result1.getLiteral("bmi").getString());" does not print any thing and "System.out.println(result1);" print so many things  which is as below


                          [numberOfColumns: 1, isConfigured: true, isPrepared: true, isRowOpen: false, isOrdered: false, isAscending false, isDistinct: false, hasAggregates: false] [columnDisplayNames: ] ""^^xsd:string "healthy"^^xsd:string "0"^^xsd:integer

Thanks
            




 

On Wed, Feb 7, 2018 at 11:33 PM, Martin O'Connor <[hidden email]> wrote:

Have you checked out the SQWRL query API documentation: https://github.com/protegeproject/swrlapi/wiki/SQWRLQueryAPI?

The column name here is "f", which follows the name of the selected variable.

To get the integer BMI value from the result, try something like the following:

result1.getLiteral("f").getInteger()

Martin

On Feb 7, 2018, at 8:48 AM, Neha Sood <[hidden email]> wrote:



Hi all
 While moving ahead with my learning, i have one question
 1. Could anyone please tell me what is column maaped to in an ontology?

Actually i run following query in javacode
queryEngine.createSQWRLQuery("Q1", "Person(?p)^height(?p,159)^weight(?p,58)^BMI(?p,?f) -> sqwrl:select(?f)")

Result of this query is :
[""^^xsd:string, "healthy"^^xsd:string, "0"^^xsd:integer]

When i run this query in Protege it return "healthy".

I expected only "healthy" in result in java code but it is coming with  extra values ""^^xsd:string, "healthy" ^^xsd:string, "0"^^xsd:integer] that i dont understand. So i thought, if i could extract value on the basis of data property name which i thought, is same as dataproperty name(BMI) in my ontology.so i put BMI here and wrote the code to print the value of BMI INFERRED FROM QUERY AS
" System.out.println(result1.getLiteral("BMI"));
But it gives exception 
"invalid column name BMI"

Actually, BMI is the Data Property of Class Person.

 Isn't Data Property equivalent to column in java?

And 

""^^xsd:string, "healthy" ^^xsd:string, "0"^^xsd:integer]  what is the meaning of this line in result?

Regards,
Neha



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Re: invalid column name in sqwrl query

Martin O'Connor-2

I would use the SQWRLQueryTab [1] component of the SWRLTab plugin [2] to interactively experiment with creating and executing rules and queries. It will give you immediate feedback on any errors.

The following clause 

physicalcare:BMI(?x,"+ "healthy"+")

is not syntactically correct. If BMI is a property of type xsd:integer then an integer literal or variable continuing one should be used.

You can find a fairly comprehensive description of the language here:


Martin


On Feb 8, 2018, at 10:04 PM, Neha Sood <[hidden email]> wrote:

Sorry that wont be feasible since i am not authorized to share ontology. But i will try to reproduce same thing with other ontology if as per your thought, its a problem with the ontology, and let you know if that extra information is coming in output or not.

One another question i have is :
1. When i add rule to the code
SWRLAPIRule rule1 = ruleEngine.createSWRLRule("S1","physicalcare:Person(?x) ^ physicalcare:height(?x, ?h) ^ swrlb:greaterThanOrEqual(?h, 158) ^ swrlb:lessThanOrEqual(?h, 159) ^physicalcare:weight(?x, ?w) ^ swrlb:lessThanOrEqual(?w, 45) -> physicalcare:BMI(?x,"+ "healthy"+")");

I get exception in code as

Error parsing SWRL rule or SQWRL query: Expecting boolean, got 'healthy'

To try with boolean, i entered '0' in the code  instead of "healthy", as below:
SWRLAPIRule rule1 = ruleEngine.createSWRLRule("S1","physicalcare:Person(?x) ^ physicalcare:height(?x, ?h) ^ swrlb:greaterThanOrEqual(?h, 158) ^ swrlb:lessThanOrEqual(?h, 159) ^physicalcare:weight(?x, ?w) ^ swrlb:lessThanOrEqual(?w, 45) -> physicalcare:BMI(?x,0)");

Now code works. 

In .owl file, since same rule exists with "healthy" value, the code is able to infer healthy from ontology. Now i do not understand how this thing is working and why code gives exception for this rule which works in protege. The datatype of BMI is a range of values 



On Fri, Feb 9, 2018 at 5:23 AM, Martin O'Connor <[hidden email]> wrote:

Can you post the ontology that you are using.

Martin

On Feb 7, 2018, at 9:24 PM, Neha Sood <[hidden email]> wrote:


1. Have you checked out the SQWRL query API documentation: https://github.com/protegeproject/swrlapi/wiki/SQWRLQueryAPI?
      Yes i checked this

 2 The column name here is "f", which follows the name of the selected variable.
     To get the integer BMI value from the result, try something like the following: 
       result1.getLiteral("f").getInteger()

     Yes, i tried this :
                      SQWRLQueryEngine queryEngine = SWRLAPIFactory.createSQWRLQueryEngine(health);
       queryEngine.createSQWRLQuery("Q1", "Person(?p)^height(?p,159)^weight(?p,58)^BMI(?p,?bmi) -> sqwrl:select(?bmi)");
                            SQWRLResult result1 = queryEngine.runSQWRLQuery("Q1");
                if (result1.next())
        {
       
        System.out.println(result1.getLiteral("bmi").getString());
                          System.out.println(result1);

                           }
 Output :
                            
                          [numberOfColumns: 1, isConfigured: true, isPrepared: true, isRowOpen: false, isOrdered: false, isAscending false, isDistinct: false, hasAggregates: false] [columnDisplayNames: ] ""^^xsd:string "healthy"^^xsd:string "0"^^xsd:integer
                     
******************************************
                              I only want to extract "healthy" from result but "System.out.println(result1.getLiteral("bmi").getString());" does not print any thing and "System.out.println(result1);" print so many things  which is as below


                          [numberOfColumns: 1, isConfigured: true, isPrepared: true, isRowOpen: false, isOrdered: false, isAscending false, isDistinct: false, hasAggregates: false] [columnDisplayNames: ] ""^^xsd:string "healthy"^^xsd:string "0"^^xsd:integer

Thanks
            




 

On Wed, Feb 7, 2018 at 11:33 PM, Martin O'Connor <[hidden email]> wrote:

Have you checked out the SQWRL query API documentation: https://github.com/protegeproject/swrlapi/wiki/SQWRLQueryAPI?

The column name here is "f", which follows the name of the selected variable.

To get the integer BMI value from the result, try something like the following:

result1.getLiteral("f").getInteger()

Martin

On Feb 7, 2018, at 8:48 AM, Neha Sood <[hidden email]> wrote:



Hi all
 While moving ahead with my learning, i have one question
 1. Could anyone please tell me what is column maaped to in an ontology?

Actually i run following query in javacode
queryEngine.createSQWRLQuery("Q1", "Person(?p)^height(?p,159)^weight(?p,58)^BMI(?p,?f) -> sqwrl:select(?f)")

Result of this query is :
[""^^xsd:string, "healthy"^^xsd:string, "0"^^xsd:integer]

When i run this query in Protege it return "healthy".

I expected only "healthy" in result in java code but it is coming with  extra values ""^^xsd:string, "healthy" ^^xsd:string, "0"^^xsd:integer] that i dont understand. So i thought, if i could extract value on the basis of data property name which i thought, is same as dataproperty name(BMI) in my ontology.so i put BMI here and wrote the code to print the value of BMI INFERRED FROM QUERY AS
" System.out.println(result1.getLiteral("BMI"));
But it gives exception 
"invalid column name BMI"

Actually, BMI is the Data Property of Class Person.

 Isn't Data Property equivalent to column in java?

And 

""^^xsd:string, "healthy" ^^xsd:string, "0"^^xsd:integer]  what is the meaning of this line in result?

Regards,
Neha



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ESSLLI 2018: Application for Grants is open

Kiril Simov-2
In reply to this post by Kiril Simov-2
[Apologies for cross-postings]

30th European Summer School in Logic, Language and Information
                             ESSLLI 2018

                        Sofia University "St. Kl. Ohridski"
                            Sofia, BULGARIA
                          August 6-17, 2018

http://esslli2018.folli.info/

http://esslli2018.folli.info/registration/

http://esslli2018.folli.info/grants/

The 30th edition of ESSLLI (European Summer School in Logic, Language and
Information) will take place from 6 August to 17 August 2018 at Sofia
University “St. Kl. Ohridski”, Sofia, Bulgaria. The European Summer School
in Logic, Language and Information is an event organized every year in a
different European country under the auspices of the Association for Logic,
Language and Information (FoLLI).

Sofia University “St. Kl. Ohridski” and the Institute of Information and
Communication Technologies, Bulgarian Academy of Sciences (IICT-BAS), will
jointly host ESSLLI 2018.

ESSLLI 2018 will be held under the patronage of Mrs. Yordanka Fandakova,
Mayor of Sofia Capital Municipality.

We are pleased to announce that the program schedule is now available for
the two weeks of the school.
Under 'Program' section you can also check the information about the
satellite Formal Grammar Conference as well as the Student Session.

The ESSLLI 2018 Organization Team
_______________________________________________
protege-user mailing list
[hidden email]
https://mailman.stanford.edu/mailman/listinfo/protege-user
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ESSLLI 2018: Call for participation

Kiril Simov-2
In reply to this post by Kiril Simov-2
[Apologies for cross-postings]

30th European Summer School in Logic, Language and Information
                             ESSLLI 2018

                        Sofia University "St. Kl. Ohridski"
                            Sofia, BULGARIA
                          August 6-17, 2018

http://esslli2018.folli.info/

The 30th edition of ESSLLI (European Summer School in Logic, Language and Information) will take place from 6 August
to 17 August 2018 at Sofia University “St. Kl. Ohridski”, Sofia, Bulgaria. The European Summer School in Logic, Language
and Information is an event organized every year in a different European country under the auspices of the Association
for Logic, Language and Information (FoLLI).

Sofia University “St. Kl. Ohridski” and the Institute of Information and Communication Technologies, Bulgarian Academy
of Sciences (IICT-BAS), will jointly host ESSLLI 2018.

ESSLLI 2018 will be held under the patronage of Mrs. Yordanka Fandakova, Mayor of Sofia Capital Municipality.

The early registration is open till May 31.

The ESSLLI 2018 Organization Team
_______________________________________________
protege-user mailing list
[hidden email]
https://mailman.stanford.edu/mailman/listinfo/protege-user
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Subject: ESSLLI 2018: Deadline for early registration is extended to June 15

Kiril Simov-2
[Apologies for cross-postings]

Please, note that the deadline for early registration is extended to June 15.

30th European Summer School in Logic, Language and Information
                             ESSLLI 2018

                        Sofia University "St. Kl. Ohridski"
                            Sofia, BULGARIA
                          August 6-17, 2018

http://esslli2018.folli.info/

The 30th edition of ESSLLI (European Summer School in Logic, Language and Information) will take place from 6 August
to 17 August 2018 at Sofia University “St. Kl. Ohridski”, Sofia, Bulgaria. The European Summer School in Logic, Language
and Information is an event organized every year in a different European country under the auspices of the Association
for Logic, Language and Information (FoLLI).

Sofia University “St. Kl. Ohridski” and the Institute of Information and Communication Technologies, Bulgarian Academy
of Sciences (IICT-BAS), will jointly host ESSLLI 2018.

ESSLLI 2018 will be held under the patronage of Mrs. Yordanka Fandakova, Mayor of Sofia Capital Municipality.

The early registration is open till June 15.

The ESSLLI 2018 Organization Team
_______________________________________________
protege-user mailing list
[hidden email]
https://mailman.stanford.edu/mailman/listinfo/protege-user